2x^2-42x-1080=0

Solution for 2x^2-42x-1080=0 equation:

2x^2-42x-1080=0

a = 2; b = -42; c = -1080;
Δ = b2-4ac
Δ = -422-4·2·(-1080)
Δ = 10404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10404}=102$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-102}{2*2}=\frac{-60}{4}
=-15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+102}{2*2}=\frac{144}{4}
=36
$